Question

chord of a circle of radius 28 cm subtends an angle of 45° at the centre of the circle. Then the area of the minor segment is--------------------- (a) 30.35 cm^2 (b) 30.81 cm^2 (c) 30.45 cm^2 (d) 30.25cm^2​

Answer 1

given, radius of circle = 28 cm

and angle A=45°

Area of sector=A /360° πr²

=45/360 × 22/ 7 × 28 × 28

=( 22 × 4 × 28 ) / 8

=2464/8

=308 cm²

therefore,

the required area of minor sector = 308 cm²

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Answer 2

given, radius of circle = 28 cm

and angle A=45°

Area of sector=A /360° πr²

=45/360 × 22/ 7 × 28 × 28

=( 22 × 4 × 28 ) / 8

=2464/8

=308 cm²

therefore,

the required area of minor sector = 308 cm²

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