chord of larger circle is 24 then tangent of smaller circle find radius of smaller circle
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Let O be the centre of concentric circles and APB be the chord of length 24 cm, of the larger circle touching the smaller circle at P.
Then, OP⊥AB and P is the mid-point of AB.
∴AP=PB=12 cm
In △OPA, we have
OA2=OP2+AP2 [by pythagorus theorem]
⇒OA2=52+122=169
⇒OA=13 cm
Hence, the radius of the smaller circle is 13 cm.
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