Question

Chords Ab and cd of a circle intersect each other at p such that AP =CD show that Ab =CD

Answer 1

In my opinion the question you've asked is wrong as both cannot be equal to CD at the same time

Answer 2

Step-by-step explanation:

Intersecting Chord Theorem:

When two chords intersect each other in a circle, the product of the segments of each chord are equal.

Here, the two chord AB and CD intersect at a point X. So, the chord AB has two segments AX and XB. Similarly, the chord CD has two segments CX and XD.

AX * XB = CX * XD

Given: AX = 8 cm AB = 14 cm CX - XD = 8 cm

So, XB = AB - AX = 6 cm and CX = 8 + XD

Using the theorem,

AX * XB = CX * XD

8 * 6 = (8 + XD) * XD

48=8∗XD+X

D

2

48=8∗XD+XD2

Let XD = x

x 2 +8x−48=0

x2+8x−48=0

x2 +12x−4x−48=0

x2+12x−4x−48=0

x(x+12)−4(x+12)=0

x(x+12)−4(x+12)=0

(x+12)(x-4) =0

x = -12 or x =4

Since x represents the length of a segment, it can't be negative. Rejecting x =-12

So x = 4

XD = 4 cm

CX = 8 + XD = 8 = 4 = 12 cm

Hence, CD = CX + XD = 12 + 4 = 16 cm

I hope it helps!

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