Chords AB and CD of a circle intersect each other in point M . The centre of the circle is P .The radius of the circle is 13cm and PM = 5cm .Find the product CM×DM .
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Step-by-step explanation:
Given :
The chords AB and CD intersect at M.
Center of the circle is P.
Radius of the circle = 13 cm
PM = 5 cm
To find :
CM * DM
Solution:
Intersecting chords theorem states that when two chords intersect each other inside a circle, the product of their segments are equal.
Also, diameter is the largest chord of the circle.
Now, draw a diameter of the circle passing through points P and M. It is the line XY as shown in the attachment.
Length XY = 2 * radius = 2 * 13 =26 cm
MY = PY - PM = 13 - 5 =7 cm
XM = XP + PM = 13 + 5 = 18 cm
By the intersecting chords theorem we have,
CM * DM = XM * YM =18 * 7 = 126
∴ CM * DM = 126
MARK IT AS BRILLIAST
Given :
The chords AB and CD intersect at M.
Center of the circle is P.
Radius of the circle = 13 cm
PM = 5 cm
To find :
CM * DM
Solution:
Intersecting chords theorem states that when two chords intersect each other inside a circle, the product of their segments are equal.
Also, diameter is the largest chord of the circle.
Now, draw a diameter of the circle passing through points P and M. It is the line XY as shown in the attachment.
Length XY = 2 * radius = 2 * 13 =26 cm
MY = PY - PM = 13 - 5 =7 cm
XM = XP + PM = 13 + 5 = 18 cm
By the intersecting chords theorem we have,
CM * DM = XM * YM =18 * 7 = 126
∴ CM * DM = 126
MARK IT AS BRILLIAST
Attachments:
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