Question

Chosen puoi
Q.4 On selling a bike for 2500 a seller inqui's a loss of 20%.. What price would have caused him to lose 30%?
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Answer 1

➤ Correct Question :-

On selling a bike for ₹2500, a seller gets a loss of 20%. What price wold have caused him to lose 30%.

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➤ Given :-

Selling price of a bike :- ₹2500

Loss percentage :- 20%

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➤ To Find :-

The selling price if sold at a loss of 30%.

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★ How to do :-

Here, we are given with the selling price and the loss percentage obtained for a bike. Later, it was sold at a loss of 30%. We are asked to find the selling price if it's sold at 30%. So, first we should find the cost price of that bike ny using the selling price and the loss percentage in first statement. Later, we can find the new selling price of the bike by using the cost price and the new loss percentage of the same. So, let's solve!!

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➤ Solution :-

Cost price of the bike :-

${\tt \leadsto \underline{\boxed{\tt \dfrac{100}{(100 - Loss \bf\%)} \times SP}}}$

Substitute the given values.

${\tt \leadsto \dfrac{100}{(100 - 20)} \times 2500}$

First, solve the bracket in the denominator and write the fraction in lowest form by cancellation method.

${\tt \leadsto \cancel \dfrac{100}{80} \times 2500 = \dfrac{5}{4} \times 2500}$

Now, multiply the remaining numbers.

${\tt \leadsto \dfrac{5 \times 2500}{4} = \dfrac{12500}{4}}$

Write the fraction in lowest form by cancellation method.

${\tt \leadsto \cancel \dfrac{12500}{4} = \underline{3125}}$

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Now, find the selling price by using the cost price and the new loss percentage.

Selling price of the bike :-

${\tt \leadsto \underline{\boxed{\tt \dfrac{(100 - Loss \bf\%)}{100} \times CP}}}$

Substitute the given values.

${\tt \leadsto \dfrac{(100 - 30)}{100} \times 3125}$

First, solve the bracket in the numerator and write the fraction in lowest form by cancellation method.

${\tt \leadsto \cancel \dfrac{70}{100} \times 3125 = \dfrac{7}{10} \times 3125}$

Multiply the remaining numbers.

${\tt \leadsto \dfrac{7 \times 3125}{10} = \dfrac{21875}{10}}$

Write the fraction in lowest form by cancellation method.

${\tt \leadsto \cancel \dfrac{21875}{10} = \pink{\underline{\boxed{\tt Rs \: \: 2187.5}}}}$

$\Huge\therefore$ The new selling price of the bike is ₹2187.5.

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$\dashrightarrow$ Some related formulas :-

$\small\boxed{\begin{array}{cc}\large\sf\dag \: {\underline{More \: Formulae}} \\ \\ \bigstar \: \sf{Gain = S.P - C.P} \\ \\ \bigstar \:\sf{Loss = C.P - S.P} \\ \\ \bigstar \: \sf{Gain \: \% = \Bigg( \dfrac{Gain}{C.P} \times 100 \Bigg)\%} \\ \\ \bigstar \: \sf{loss \: \% = \Bigg( \dfrac{loss}{C.P} \times 100 \Bigg)\%} \\ \\ \bigstar \: \sf{S.P = \dfrac{100+Gain\%}{100} \times C.P} \\ \\ \bigstar \: \sf{C.P =\dfrac{100}{100+Gain\%} \times S.P}\end{array}}$