chp-trignometery
pls anyone solve this
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Step-by-step explanation:
If y tan θ = 3/4
In △ABC
Right angle at B
Perpendicular = CB = 3
Base = AB = 4
Hypotenuse = AC = ?
By Pythagoras Theorem:
AC² = AB² + CB²
=> AC² = 4² + 3²
=> AC² = 16 + 9 = 25
=> AC = √5
Sin θ = 3/5
Cos θ = 4/5
Find 3 Sin θ – 4 Cos θ ?
=> (3 × 3/5) – (2 × 4/5)
=> 9/5 – 8/5
=> 1/5 = answer
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