Question

cigi UI W
lungest side.
The base of an isosceles triangle is 48 cm and one of its equal sides is 30 cm. Find the area
of the triangle.​

Answer 1

Answer:

area of the triangle is 270 sq cm

Step-by-step explanation:

area of the triangle = base * hieght/2

we need to find height here

take a perpendicular bisector from base, it will form two right angled triangle. now we can find the hieght using Pythagoras theorem

${30}^{2} = (48 \div 2)^{2} + {x }^{2} \\ {x}^{2} = {30}^{2} - {24}^{2} \\ {x}^{2} = 900 - 576 \\ {x}^{2} = 324 \\ x = \sqrt{324} \\ x = 18$

area of the triangle is

$a = \frac{1}{2} bh \\ a = 30 \times 18 \div 2 \\ = 270cm^{2}$

area of the triangle is 270 sq cm

Answer 2

Answer:

see the attachment for ur answer

Step-by-step explanation:

drop some ❤️