Question

cindy has two bags .
in the first bag there are 3 red balls and 7 green balls.
in the second there are 4 red balls and 5 green balls
cindy takes a random ball from the first bag
she takes at random a ball from the second bag.

what is the probability that cindy takes out two balls of the same colour.

?/90

Answer 1

Step-by-step explanation:

Answer:

Step-by-step explanation:

There are a total of 10 balls in the first bag, so P(1 red) = 3/10 and P(1 green) = 7/10.There are a total of 9 balls in the second bag, so P(2 red) = 4/9 and P(2 green) = 5/9.P(1 red & 2 red) = 3/10 × 4/9 = 12/90 = 2/15P(1 red & 2 green) = 3/10 × 5/9 = 15/90 = 1/6P(1 green & 2 red) = 7/10 × 4/9 = 28/90 = 14/45P(1 green & 2 green) = 7/10 × 5/9 = 35/90 = 7/18

I hope you understand it!