circle equation is x^2+y^2-5x+8y+6 find the center of the circle
can anyone please explain it clearly
Answers
Answered by
1
Answer:
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Step-by-step explanation:
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Answered by
6
Answer:
centre (5/2, -4)
Step-by-step explanation:
The equation of a Circle in standard form is
(x-a)²+(y-b)² = r²
Where ,( a,b) are coordinate of the centre and , r is radius of the Circle.
★ Use the method of completing square method .
∴ x²+y² -5x + 8y +6 = 0
⟹x² - 2*5/2* x + (5/2)² -( 5/2)²+ y² + 2* 4* y + 4² -4² +6 = 0
- ⟹ (x-5/2)² + (x+4)² =( 5/2)² + (4)² -6
- ⟹ (x-5/2)² + (x+4)² = 25/4+16-6
- ⟹ (x-5/2)² + (x+4)² = 65/4
★ In standard form .
centre (5/2,-4) and radius 1/2√65
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