Question

Circle the atom in each pair that has the largest atomic radius. a, Al or B
b.. Na or Al
c. S or 0
d. 0 or F
e. Br or Cl
f. Mg or Ca
g. Ca⁺² or Ca
h. Cl or Cl⁻¹

Answer 1

The given question can be solved by the properties of atomic radius.

• Atomic radius is defined as the shortest distance between the center of the nucleus and the outermost shell of an atom.
• Generally, the atomic radius increases across the group from top to bottom.
• The atomic radius of atoms generally decreases from left to right in a particular period of the periodic table.
• The atomic radius of a cation is less than the atomic radius of the respective parent atom.
• The atomic radius of an anion is greater than the atomic radius of the respective parent atom.
• For a similar number of electrons, The greater the charge of anion the highest is the size. The greater the charge of the cation the smaller is the size.

Example$N^{-3} > O^{-2} >F^{-1} >Na^{+1} >Mg^{+2} >Al^{+3}$.

Considering the above points we can find the atom with the largest atomic radius.

a. Al or B  ( Al has a higher atomic radius because size increases across a group from top to bottom)

b. Na or Al (Na has a higher atomic radius because across a period size increases from left to right)

c. S or O ( Sulfur has a higher atomic radius because size increases across a group from top to bottom)

d. O or F ( O has a higher atomic radius because across a period size increases from left to right)

e. Br or Cl(Br has a higher atomic radius because size increases across a group from top to bottom)

f. Mg or Ca(Ca has a higher atomic radius because size increases across a group from top to bottom)

g. $Ca^{+2}$ or Ca (  Ca has a higher atomic radius because the size of a cation is less than the size of its parent atom)

h. Cl or $Cl^{-1}$ ( $Cl^{-1}$ has a higher atomic radius because the size of an anion is greater than the size of its parent atom).

Answer 2

Answer:

q

Explanation:

answer

fgnjtyxww wghj shuy