Question

Circular disk is rotating with an angular velocity ω in vertical plane. Velocity of point P is

Answer 1

Velocity of point P is 2Rω

Explanation:

For a rigid disc rotating around a pivot with an angular velocity ω, all its point will be rotating w.r.t. to the pivot with an angular velocity ω

Thus, the angular velocity of point P = ω

The distance of point P from the pivot = 2R

Therefore, the linear velocity of point P

$v=\omega\times 2R$

or, $v=2\omega R$

Hope this answer is helpful.

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Q: A thin uniform circular disc of Mass M and radius R is rotating in a Horizontal plan about an axis passing through it's center and perpendicular to it's plane with an angular velocity.  Another Disc of the same dimensions but of Mass M/4 is placed gently on the first disc co-axially.  Show that angular velocity of the system is 4/5w.

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