The product of two consecutive integers is 90.find the integers
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Answer:
Step-by-step explanation:
Let the two consecutive integers be x and (x+1)
Then according to the Question ,
x × (x+1) = 90
On Opening the bracket,
x² + x = 90
x²+x-90 = 0
On spliitting the middle term to solve the quatratic equation ,
x²+ 10x - 9x -90 = 0
x(x+10) - 9(x+10) = 0
(x+10) (x-9) = 0
Therefore,
x = -10
and
x = 9
If , x = -10
Then the numbers will be
x = -10
and
(-10+ 1) = -9
If , x = 9
Then the numbers will be
x = 9
and
(9+1) = 10
So the consecutive integers can be
9,10
or
-10,-9
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