Question

Circular field of radius 41m has a circular path of uniform 5m along and inside its boundary.find the area of the path

Answer 1

HEY Buddy....!! here is ur answer

Answer : 1210 m²

Given that : Radius of Circular field = 41m and has a circular path of a uniform 5m along and inside it's.

So, the inner radius = 41–5 = 36 m

Area of Path = Area of external Circle – Area of inner circle

$\pi \times {(41)}^{2} - \pi \times {(36)}^{2} \\ \\ = > \pi( {41}^{2} - {36}^{2} ) \\ \\ = > \frac{22}{7} \times (1687 - 1296) \\ \\ = > \frac{22}{7} \times 385 \\ \\ = > 22 \times 55 \\ \\ = > 1210 \: {m}^{2}$

So, the area of path will be 1210 m²

I hope it will be helpful for you...!!

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