Question

Circumference of a semicircle is 216 MTS then its radius is

Answer 1

$\huge{\mathcal{Hi\: there!}}$

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Circumference of Semicircle

= $\mathsf{ \frac{circumference \: of \: circle}{2} }$

⇒ Circumference of semicircle = 2πr /2

⇒ Circumference of circle = πr

Now,

⇒ πr = 216

$⇒ \mathsf{ \frac{22}{7} \times r = 216 } \\ \\ ⇒ \mathsf{22r = 216 \times 7} \\ \\ ⇒ \mathsf{r = \frac{1512}{22} } \\ \\ ⇒ \mathsf{r = 68.7}$

Hence, the radius of the Semicircle is 68.7 m.

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Thanks for the question !

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Answer 2

Here is the answer

We know that,

Circumference of semi circle $\bf{ = \frac{Circumference \: of \: circle}{2} }$

Circumference = 2 π r

Therefore,

Circumference of semi circle
$\bf{= \frac{2 \: \pi \: r}{2}} = \pi \: r$

Thus,
Circumference of semi circle is π r

Now,

Coming to your question,

Circumference = 216
π = 22/7
r = ?

$\bf {\therefore216 = \frac{22}{7} \times r}$

$\bf{ \frac{216 \times 7}{22} = r}$

$\bf{ \frac{1512}{22} = r}$

$\bf{ 68.72 = r}$

Thus,
$\bf{ r \: \approx \: 68.7}$

Radius = 68.7 cm.

Thanks!!