if cosecQ + cotQ = m and cosecQ - cotQ = n prove that mn = 1
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Answered by
17
Hii !!
Cosec Q + Cot Q = m
And,
Cosec Q - Cot Q = n
To Prove :- mn = 1
LHS = mn
=> ( Cosec Q + CotQ ) ( Cosec Q - CotQ )
=> ( Cosec²Q) - ( Cot²Q) [( a + b) (a - b )]
=> 1
Hence,
MN = 1 ......Proved......
Cosec Q + Cot Q = m
And,
Cosec Q - Cot Q = n
To Prove :- mn = 1
LHS = mn
=> ( Cosec Q + CotQ ) ( Cosec Q - CotQ )
=> ( Cosec²Q) - ( Cot²Q) [( a + b) (a - b )]
=> 1
Hence,
MN = 1 ......Proved......
sawansehrawat338:
hi
Answered by
6
HEY THERE!!!
Question:
if cosecQ + cotQ = m and cosecQ - cotQ = n prove that mn = 1
Method Of Solution:
Multiplication of numbers
MN= 1
Substitute the Given value in Equation!
mn
= (cosec∅+cot∅) (cosec∅-cot∅)
= cosec∅(cosec∅-cot∅) + cot∅(cosec∅-cot∅)
= cosec²∅-cosec∅.cot∅+cosec∅.cot∅ - cot²∅
= cosec²∅- cot²∅
= 1
Here, used identity!
(cosec²∅-cot²∅)
= 1
Here, It's Proved!
Question:
if cosecQ + cotQ = m and cosecQ - cotQ = n prove that mn = 1
Method Of Solution:
Multiplication of numbers
MN= 1
Substitute the Given value in Equation!
mn
= (cosec∅+cot∅) (cosec∅-cot∅)
= cosec∅(cosec∅-cot∅) + cot∅(cosec∅-cot∅)
= cosec²∅-cosec∅.cot∅+cosec∅.cot∅ - cot²∅
= cosec²∅- cot²∅
= 1
Here, used identity!
(cosec²∅-cot²∅)
= 1
Here, It's Proved!
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