Question

claculate the momentum of particle og de brogli wave lenght 0.1 nanometer

Answer 1

✴️Hey.. Abhishek...✴️
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☛Here is your answer dear:-----

☑️Given,
De broglie's Wavelength = 0.1 nm
===> 0.1 × 10^-9m
◼️Then,
According to de broglie's equation ===>

☑️Momentum = Planck's constant/wavelength

And we know,

⚫Planck's constant = 6.6 × 10^-34

Now,

➡️Momentum = 6.6 × 10^-34/0.1 × 10^-9
✔️ ( p) = 66 × 10^-25kgm/s

Hope it will be helpful to you!
Thanks!!☺️
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