the length of a rectangular field is 8 metres less than twice its breadth if the perimeter of the rectangular field is 56 cm find its length and breadth
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l=2b-8
p=56
2(l+b)=56
2(2b-8+b)=56
2(3b-8)=56
3b-8= 56/2
3b-8=28
3b=28+8=36
3b=36
b=36/3
b=12
l=2b-8
l=2(12)-8
l=24-8
l=16
l=16,b=12 is answer
p=56
2(l+b)=56
2(2b-8+b)=56
2(3b-8)=56
3b-8= 56/2
3b-8=28
3b=28+8=36
3b=36
b=36/3
b=12
l=2b-8
l=2(12)-8
l=24-8
l=16
l=16,b=12 is answer
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