Question

class 10-find the following pair of linear equations by substitution method
3x-y=3
9x-3y=9
in this, if we consider the equation 2 what will be the resulting answer?

Answer 1

Hey there !!

Elimination by substitution :-

9x-3y=9  -------> [ 1 ] 

3x - y = 3           ------> [ 2 ]

3x = 3 + y 

x =  [3 + y]/ 3

Put this value in equation [1 ]

9 × { [3 + y]/ 3 } - 3y = 9

 [27+9 y ] / 3 - 3y = 9

9 [ 3 + 1 y ]  / 3 = 9

3 [ 3 + 1 y ] = 9

9 + 3y = 9

3y = 9 - 9

3y = 0

y = 0

x = y + 3 / 3

    = 0 + 3 / 3

    = 1

Hence ,

x = 1 , y = 0

Hope it's helps you

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