The difference between 472
and the number formed to
interchanging the digits
at Tens and ones place is______
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Answer:
Let, the digit at tens place be x and the digit at units place be y in the original number.
Then the original number =10+y, and the new number obtained by interchanging the digits =10y+x.
By the data, the digit at tens place is double the digit at units place.
∴x=2y
∴x−2y=0 ............. (1)
Again, new number = original number - 27
∴10y+x=10x+y−27
∴10y+x−10x−y=−27
∴−9x+9y=−27 ∴x−y=3 ........... (2)
Subtracting eq. (1) from eq. (2),
x−y=3
x−2y=0
- + -
__________
y=3
Substituting y=3 in x−2y=0
∴x−2(3)=0
∴x−6=0
∴x=6
Then, the original number =10x+y=10(6)+3=63
Hence, the original number is 63.
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