Question

Class 10
Maths
Ch-6
Subject
Traingles
the
Exercise 6.3- 15th Question
A vertical pole of a length
Gm casts shadow 4m long
the ground and at
same time
a tower casts a
shadow 28m long.
28m long. Find the
height of
of the tower.




I want this answer with explanation.
​

Answer 1

Answer:

Are you really in class 10

Step-by-step explanation:

I am also in class 10 but we have not yet started our 6 lesson

If you have completed 3.3 exercise of 3 lesson please send it to me.

Answer 2

Answer:

Height of pole=AB=6 m

Length of shadow of pole =BC=4 m

Length of shadow of tower=EF=28 m

In △ABC and △DEF

∠B=∠E=90

∘

both 90

∘

as both are vertical to ground

∠C=∠F (same elevation in both the cases as both shadows are cast at the same time)

∴△ABC∼△DEF by AA similarity criterion

We know that if two triangles are similar, ratio of their sides are in proportion..So,

DE

AB

=

EF

BC

⇒

DE

6

=

28

4

⇒DE=6×7=42 m

Hence the height of the tower is 42 m