English, asked by sasidhary54, 2 months ago

class 10 maths full fromula​

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Answered by aaizaareej59
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Answer:

Algebraic formulas:

(a+b)2 = a2 + b2 + 2ab

(a-b)2 = a2 + b2 – 2ab

(a+b) (a-b) = a2 – b2

(x + a)(x + b) = x2 + (a + b)x + ab

(x + a)(x – b) = x2 + (a – b)x – ab

(x – a)(x + b) = x2 + (b – a)x – ab

(x – a)(x – b) = x2 – (a + b)x + ab

(a + b)3 = a3 + b3 + 3ab(a + b)

(a – b)3 = a3 – b3 – 3ab(a – b)

(x + y + z)2 = x2 + y2 + z2 + 2xy + 2yz + 2xz

(x + y – z)2 = x2 + y2 + z2 + 2xy – 2yz – 2xz

(x – y + z)2 = x2 + y2 + z2 – 2xy – 2yz + 2xz

(x – y – z)2 = x2 + y2 + z2 – 2xy + 2yz – 2xz

x3 + y3 + z3 – 3xyz = (x + y + z)(x2 + y2 + z2 – xy – yz -xz)

x2 + y2 =½ [(x + y)2 + (x – y)2]

(x + a) (x + b) (x + c) = x3 + (a + b +c)x2 + (ab + bc + ca)x + abc

x3 + y3= (x + y) (x2 – xy + y2)

x3 – y3 = (x – y) (x2 + xy + y2)

x2 + y2 + z2 -xy – yz – zx = ½ [(x-y)2 + (y-z)2 + (z-x)2]

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Basic formulas for powers

pm x pn = pm+n

{pm}⁄{pn} = pm-n

(pm)n = pmn

p-m = 1/pm

p1 = p

P0 = 1

nth term = a + (n-1) d

Sn = n/2 [2a + (n-1) d]

Other Trigonometric formulas:

sin(90° – θ) = cos θ

cos(90° – θ) = sin θ

tan(90° – θ) = cot θ

cot(90° – θ) = tan θ

sec(90° – θ) = cosecθ

cosec(90° – θ) = secθ

sin2θ + cos2 θ = 1

sec2 θ = 1 + tan2θ for 0° ≤ θ < 90°

Cosec2 θ = 1 + cot2 θ for 0° ≤ θ ≤ 90°

Circles Formulas For Class 10

Circumference of the circle = 2 π r

Area of the circle = π r2

Area of the sector of angle θ = (θ/360) × π r2

Length of an arc of a sector of angle θ = (θ/360) × 2 π r

(r = radius of the circle)

Sphere Formulas

Diameter of sphere 2r

Surface area of sphere 4 π r2

Volume of Sphere 4/3 π r3

Cylinder Formulas

Curved surface area of Cylinder 2 πrh

Area of two circular bases 2 πr2

Total surface area of Cylinder Circumference of Cylinder + Curved surface area of Cylinder = 2 πrh + 2 πr2

Volume of Cylinder π r2 h

Cone Formulas

Slant height of cone l = √(r2 + h2)

Curved surface area of cone πrl

Total surface area of cone πr (l + r)

Volume of cone ⅓ π r2 h

Cuboid Formulas

Perimeter of cuboid 4(l + b +h)

Length of the longest diagonal of a cuboid √(l2 + b2 + h2)

Total surface area of cuboid 2(l×b + b×h + l×h)

Volume of Cuboid l × b × h

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