Question

class 10 maths solution in hindi

Answer 1

Given :  PQR is right angled triangle ∠P = 90°

PQ = √3  , QR = 2 , PR = 1  

To Find : SinQ , CosQ  , TanR ,  SinR

Solution:

SinQ  = PR/QR  =  1/2

CosQ = PQ / QR  = √3 / 2

TanR  = PQ / PR  =  √3  /1  =  √3  

Sin R = PQ/  / QR  = √3 / 2  

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