the perimeter of a triangular field is 840cm and its sides are in the ratio 6:7:8find the area of the field
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perimeter of the rectangular field is 840cm
let tle side be x
then sides are 6x,7x and 8x
perimeter =
6x+7x+8x=840
=21x=840
x=840cm ÷21= 40cm
sides= 6x = 6×40=240cm
7x=7×40=280cm
8x=8×40=320cm
sides are 240cm, 280cm and 320cm
area=1/2 × b×h.
let tle side be x
then sides are 6x,7x and 8x
perimeter =
6x+7x+8x=840
=21x=840
x=840cm ÷21= 40cm
sides= 6x = 6×40=240cm
7x=7×40=280cm
8x=8×40=320cm
sides are 240cm, 280cm and 320cm
area=1/2 × b×h.
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