Question

【Class 10】

NCERT

● Describe an activity with diagram to illustrate that the reaction of metal carbonates and metal bicarbonates with acids produces carbon dioxide. Write the relevant equations of all the reactions that take place. Name any two forms in which calcium carbonate is found in

nature...​

Answer 1

$\huge \boxed { \bf{answer}}$

$\boxed{ \bf{activity} \div }$

AIM :

>> To show Acid reacts with metal carbonate to liberate carbon dioxide.

MATERIALS REQUIRED :

>> CaCO3 (marble chips), Woulfe-bottle, thistle funnel, dilute HCl, gas jar,
matchbox, delivery tube bent at two right angles, lime water.

PROCEDURE :

>> Take two test tube and level them as A and B

>> Take an amount of sodium carbonate (Na2CO3) in test tube A and than take the same amount of Sodium Hydrogen Carbonate (NaHCO3) in test tube B.

>> Add about 2 mL of dilute HCl to both the test tubes.

>> Pass the gas produced in each case through lime water (calcium hydroxide solution) as shown in diagram provided above.

>> Now, record your observations.

$\boxed{ \bf{reaction \: involved \div }}$

CaCo3 + 2HCl --------> CaCl2 + H2O + CO2

Ca(OH)2 + CO2 ------> CaCO3 + H20.

$\boxed{ \bf{conclusion \div }}$

>> Metal carbonates react with dilute acids to liberate carbon dioxide.

◆>> Limestone, chalk, marble are different forms of calcium carbonate.

>> All metal carbonates and hydrogen

carbonates react with acids to form corresponding salts, water and carbon dioxide.

Answer 2

Answer:

Arrange the apparatus as shown below

Sodium carbonate is added to hydrochloric acid in a

boiling tube which is immediately stoppered.

 A delivery tube from the first boiling tube in dipped into

limewater in the second boiling tube.

 

Limewater is used to test for carbon dioxide. The presence

of carbon dioxide is determined when a white precipitate forms.

Reaction in the first boiling test tube:

Na2CO3 + 2HCl = 2NaCl + CO2 + H2O

Reaction in the second boiling tube:

CO2 + Ca(OH)2 = CaCO3 + H2O

The white precipitate is CaCO3

Explanation: