Question

class 10 ques2 ex 2.1

Answer 1

Q.2ANS
let x is greater then 6 by euclid's division lemma we have,x=6q+r where0 is greater than equals to r is greater than 66q+3 or 6q+1 or 6q+2 or 6q+3 or 6q+4 or 6q+5.now,6q is an even integer being a multiple of 2 we know that the sum of even and odd integer is always an odd integer.therefore, 6q=1 6q+3 and 6q+5 are odd integers
hence any odd positive integer is in the form of 6q+1 or 6q+3 or 6q+5