Question

Class 10 Trigonometry​

Answer 1

LHS = sinA-cosA+1/sinA+cosA-1

divide both numerator and denominator by cosA

Solving,

LHS=(tanA−1+secA)/(tanA+1−secA)

Now,

sec2A=1+tan2A

sec2A−tan2A=1

Using above relation at denominator of LHS

LHS=(tanA−1+secA)/(tanA−secA+sec2A−tan2A)

LHS=(tanA−1+secA)/[(secA−tanA)(−1+secA+tanA)]

LHS=1/(secA−tanA)

LHS=RHS