Class 10th exercise 12.3 qus 5
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Answer:
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Step-by-step explanation:
Solution:
Side of the square = 4 cm
Radius of the circle = 1 cm
Four quadrant of a circle are cut from corner and one circle of radius are cut from middle.
Area of square = (side)2= 42 = 16 cm2
Area of the quadrant = (πR2)/4 cm2 = (22/7)×(12)/4 = 11/14 cm2
∴ Total area of the 4 quadrants = 4 ×(11/14) cm2 = 22/7 cm2
Area of the circle = πR2 cm2 = (22/7×12) = 22/7 cm2
Area of the shaded region = Area of square – (Area of the 4 quadrants + Area of the circle)
= 16 cm2-(22/7) cm2+(22/7) cm2
= 68/7 cm2
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