Physics, asked by krish200631, 6 months ago

Class 10TH science
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Answered by Anonymous
1

25. V = 4V,  

R1 = 6 ohm, R2 = 8 ohm (in series)

(a) Combined resistance, R = R1 + R2 = 6+2 = 8ohm

(b) Current flowing, I = V/R = 4/8=0.5amp

(c) p.d. across 6ohm resistor = I x R1 = 0.5 x 6 = 3 V

26. V = 6V

R1 = 3 ohm, R2 = 6 ohm (in parallel)

(a) Combined resistance,

1/R = 1/R1 + 1/R2

1/R = 1/3 + 1/6 = 3/6 = 1/2

R = 2 ohm

(b) Current flowing in the main circuit, I = V/R = 6/2 = 3 A

(c) Current flowing in 3 ohm resistor = V/R1 = 6/3 = 2 A

27. I = 6v

R1 = 2 Ω , R2 = 3 Ω

(a) Combined resistance, R tot = 2 + 3 = 5 Ω

(b) I = v/Rtot = 10/5 = 2A

(C) p.d. across 2 Ω resistor = I × R1 = 2 × 2 = 4v

(d) p.d. across 3 Ω resistor = I × R2 = 2 × 3 = 6v

28. Total current flowing through circuit, I = 6 A

R1 = 3 ohm, R2 = 6 ohm

(a) Combined resistance R is

1/R=1/3+1/6

1/R=3/6

R=2ohms

(b) p.d. across the combined resistance = IR = 6 x 2 = 12 V

(c) p.d. across the 3 ohm resistor = p.d. across the combined resistance = 12 V

(d) Current flowing through the 3 ohm resistor = V/R1 = 12/3 = 4 A

(e) Current flowing through the 6 ohm resistor = V/R2 = 12/6 = 2 A

Answered by Anonymous
0

\huge\red{Answer}

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☆☞ [ Verified answer ]☜☆

If two resistors or impedances in series are unequal and of different values, then the total or equivalent resistance, RT is equal to the mathematical sum of the two resistances. That is equal to R1 + R2.

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