class 10th
Trigonometry
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Given:-
Here, we have
️ABC a right angled triangle
Right - angled at B
AB = 24cm
BC = 7cm
To Find :-
(i)sin A
(ii)cos A
Solution :-
In ️ABC ,By Pythagoras theorem
AC² = AB² + BC²
AC² = 24² + 7²
AC² = 576 + 49
AC² = 625
AC = 25
Here, we have hypotenuse (AC) = 25
Therefore,
sin A = P/H = 7/25
cos A = B/H = 24/25
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