Question

class 11 question find the relative error if a=4+_0.1 ,b=2+_0.5,c=1+_0.1
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Answer 1

Answer:

The relative error will be =3/8

Explanation:

Relative error =deltaa/a+deltab/b+deltac/c

=0.1/4+0.5/2+0.1/1

=1/40+5/20+1/10

=(1+10+4)/40

=15/40

=3/8