Class 11th, a constant force of 200 n acts on a body if chaes velocity of body from 20 km/h to 50km/h find workdone if cacceleration is 3km/h^2
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Work =force × distance...........1
Force is given but distance is not
so,
S=vit+1/2at^2..............2
t=?
Vf=Vi+at
t=Vf-Vi/a
t=50-20/3
t=30/3
t=10s
put in eq 2
S=20(10)+1/2(3)(10)^2
S=200+1/2(3)(100)
S=200+1/2(300)
S=200+150
S=350km
putting the value of distance in eq 1
Work =(200)(350)
You will get the answer
Force is given but distance is not
so,
S=vit+1/2at^2..............2
t=?
Vf=Vi+at
t=Vf-Vi/a
t=50-20/3
t=30/3
t=10s
put in eq 2
S=20(10)+1/2(3)(10)^2
S=200+1/2(3)(100)
S=200+1/2(300)
S=200+150
S=350km
putting the value of distance in eq 1
Work =(200)(350)
You will get the answer
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