class 7 chapter 2 exercise 2.5 question 7
Answers
Answered by
1
Step-by-step explanation:
Ex 2.5 Class 7 Maths Question 7.
Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?
Solution:
Distance travelled by Dinesh from A to C
= AB + BC
= 7.5 km +- 12.7 km
= 20.2 km
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 1
Distance travelled by Ayub from A to C
= AD + DC
= 9.3 km + 11.8 km = 21.1 km
Since 21.1 km > 20.2 km.
Hence, Ayub travelled more distance
hope it helps you
Answered by
0
Answer:
snskskskskskaksksks
Step-by-step explanation:
djkkkkkkkk#(#(5+#(_(_(to+$(_"
Similar questions