Question

class 8 14.2 question no.2

Answer 1

konsa part jaldi btatao

Answer 2

Answer:

(i) 4p2 – 9q2

= (2p)2 – (3q)2

= (2p – 3q) (2p + 3q)

[∵ a2 – b2 = (a + b)(a – b)]

(ii) 63a2 – 112b2

= 7(9a2 – 16b2)

= 7 [(3a)2 – (4b)2]

= 7(3a – 4b)(3a + 4b)

[∵ a2 – b2 = (a + b)(a – b)]

(iii) 49x2 – 36 = (7x)2 – (6)2

= (7x – 6) (7x + 6)

[∵ a2 – b2 = (a + b)(a – b)]

(iv) 16x5 – 144x3 = 16x3 (x2 – 9)

= 16x3 [(x)2 – (3)2]

= 16x3(x – 3)(x + 3)

[∵ a2 – b2 = (a + b)(a – b)]

(v) (l + m)2 – (l – m)2

= (l + m) – (l – m)] [(l + m) + (l – m)]

[∵ a2 – b2 = (a + b)(a – b)]

= (l + m – l + m)(l + m + l – m)

= (2m) (2l)

= 4ml

(vi) 9x2y2 – 16 = (3xy)2 – (4)2

= (3xy – 4)(3xy + 4)

[∵ a2 – b2 = (a + b)(a – b)]

(vii) (x2 – 2xy + y2) – z2

= (x – y)2 – z2

= (x – y – z) (x – y + z)

[∵ a2 – b2 = (a + b)(a – b)]

(viii) 25a2 – 4b2 + 28bc – 49c2

= 25a2 – (4b2 – 28bc + 49c2)

= (5a)2 – (2b – 7c)2

= [5a – (2b – 7c)] [5a + (2b – 7c)]

= (5a – 2b + 7c)(5a + 2b – 7c)

Hope it helps you

Pls mark as brainliest it took me 30 mins to write