Math, asked by zainabzeena2003, 1 year ago

CLASS 9 MATHEMATICS ( POLYNOMIALS )
Q) If x – 3 and x − 1/3 are both factors of px^2 + 5x + r , then show that P = r. PLEASE REPLY SOON. I NEED IT URGENTLY

Answers

Answered by AJAYMAHICH
1
This question requires that you find the values of p and r, which i assume before solving, are equal.

Now, if x-3 and x-1/3 are both factors to this expression , it means their division gives a value of zero.

Now lets use x-3

>>> let x-3=0.

>>> x=3

Now substitute x=3 into the expression

>>>> Px^2+5x+r

>>> P (3)^2 + 5(3) +r = 0

>>> 3p+ r + 15= 0

>>> 9p+r= -15 ……..(1) simultaneous eqn

Now use x-1/3.

Let x-1/3=0

>>> x=1/3

Now substitute x=1/3 into the polynomial

>>> P(1/3)^2+ 5(1/3) + r=0

>>> P(1/9)+ 5/3 +r =0

>>> P(1/9) + r= -5/3

>>> P + 9r = -15 …(2) simultaneous eqn

Subtract (1) from (2)

>>> 8p - 8r = 0

>>> 8p = 8r

>>> p = r

As required.

khalidmalik43786: plz yrr
AJAYMAHICH: chal futt le yhan se
AJAYMAHICH: ladki ko smjhana koi preshan krna nhi hots
AJAYMAHICH: hota
khalidmalik43786: bhanke lore sale mard h toh addres likh raha hu mbd pakbara up teri gand
zainabzeena2003: Thank you so much for your help
zainabzeena2003: Could u just explain how P(1/9)+r became P+9r and -5/3 became -15?
AJAYMAHICH: hmmm
AJAYMAHICH: we solve this equation P(1/9)+r = -5/3
AJAYMAHICH: taking lcm 9 and then (P+9r) / 9 = -5/3
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