Class 9 ncert exercise 12.2 question 3
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Answer:
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Step-by-step explanation:
Hi i am kutti going to answer this question
Q.Radha made a picture of an aeroplane with coloured papers as shown in the figure find the total area of the paper used
solutions: Perimetre =2s=(5+5+1) cm
Perimetre =11cm
S=11cm/2=5.5cm
Area of the triangle = √s(s-a)(s-b)(s-c)
√5.5(5.5-5)(5.5-5)(5.5-1)
√5.5(0.5)(0.5)(4.5) cm
0.75√11cm
(0.75×3.317)cm
=2.488cm (approx)
For quadrilateral 2
This qudrilateral is trapezium
perpendicular height of a parallogram+ Area of equilateral triangle
Area =l×b=(6.5×1)cm
=6.5cm
For quadrilateral 3
This quadrilateral is a trapezium
Perpendicular height of a parallogram =√1)2-(0.5) cm
area of parallelogram plus area of equality triangle
(0.866)1+√3/4(1)2
0.866+0.4333
=1.299cm
Area of triangle 4 =Area of triangle 5
(1/2×1.5×6) cm
=4.5cm