Question

class 9th



answer plz​

Answer 1

Answer:

proof: ABCD Is A //gm.

AB//CD , AC Is A Transversal

Therefore, Angle BAC = Angle DCA (Alternate Interior Angle)

AD//BC , AC Is A Transversal

Therefore, Angle DAC = Angle ACB (Alternate Interior Angle)

∆ABC ∆ADC

Angle BAC = Angle DCA

Angle DAC = Angle ACB

AC = AC (Common Side)

Therefore, ∆ABC =~ ∆ADC (ASA Congruency Rule)

∆ABC Is Congruent To ∆ADC

Note: Please Give Me The Best Answer

Answer 2

data :-ABCD is a parallelogram

to prove:-triangle ABD is congruent to triangle BCD

proof:-in triangle ABD and triangle BCD

AB=DC (opp sides are equal)

AD=BC (opp sides are equal)

BD=BD (common)

therefore ABDis congruent to BCD

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