Question

class 9th math chapter 12 ex 12.1 solve​

Answer 1

Step-by-step explanation:Third sidec=32 cm-(8+11) cm=13 cm

so 2s=32i.e, s=16 cm,

s-a=8cm,

s-b=5cm,

s-c=3cm,

therefore area of triangle√s(s-a)(s-b)(s-c)

√16×8×5×3=8√30 cm^2

Answer 2

Step-by-step explanation:

Here we have perimeter of the triangle 32cm

a=8cm, b=11cm

third side c =32cm ---(8+11) =13 cm

2s=32 ,s=16cm

s-a=8cm

s-b=5cm

s-c=3 cm

√16×8×5×3cm²=8√30 cm²