class interval 0-20 20-40 40-60 60-80 80-100 100-120 and frequency 6 8 10 12 6 5 3 draw more than and less then type ogive hence find the median
Answers
Mismatch in Data
Step-by-step explanation:
0- 20 6
20 - 40 8
40 - 60 10
60 - 80 12
80 -100 6
100 - 120 5
3
Class intervals given are 6
frequencies given are 7
So mismatch in data
Less than ogive
The points with the upper limits of the class are plotted on x axis and the corresponding less than cumulative frequencies on y axis.
The points are joined by free hand smooth curve to give less than cumulative frequency curve or the less than Ogive
More than ogive
The points with the Lower limits of the class are plotted on x axis and the corresponding more than cumulative frequencies on y axis.
The points are joined by free hand smooth curve to give more than cumulative frequency curve or the More than Ogive
Learn more:
what type of ogive do we call a graph which has been drawn ...
https://brainly.in/question/13741836
what type of ogive do we call a graph which has been drawn ...
https://brainly.in/question/13741836
The median of the given frequency distribution is 61.
Class Frequency less than cumulative more than cumulative
0-20 6 6 50
20-40 8 14 44
40-60 10 24 36
60-80 12 36 26
80-100 6 42 14
100-120 5 47 8
120-140 3 50 3
- Plot less than cumulative frequencies against upper limits of classes and more than cumulative frequencies against lower limits of classes.
- Join these points and drop a perpendicular from the point where these two curves intersect.
- This line meets the x-axis at 61.
- Therefore, median of given frequency distribution is 61(approximately).
