class intervals-
0-5,
6-11,
12-17,
18-23,
24-29
frequency 13,10,15,8,11 find the upper limit of median class
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Answer:
Classes are not continuous, hence make them continuous by adding 0.5 to the upper limits and subtracting 0.5 from the lower limits.
C.I Frequency Cumulative Frequency
0−5.5 13 13
5.5−11.5 10 23
11.5−17.5 15 38
17.5−23.5 08 46
23.5−29.5 11 57
Total ∑f=57
Class interval can't be negative hence the first C.I. is starting from 0.
Now to find median we calculate
2
∑f
=
2
57
=28.5
∴ Median class 11.5−17.5
So, the upper limit is 17.5
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