Question

class ten ncert chapter two optional exercise last question plzzzzz ​

Answer 1

Hello

x4−6x3+16x2−25x+10 is divided by another polynomial x2−2x+k, the remainder comes out to be x + a find k and a.

Sol. Let us divide x4−6x3+16x2−25x+10 by x2−2x+k

19

So, remainder = (2 k – 9) x – (8 – k) k + 10

But the remainder is given as x + a.

On comparing their coefficients , we have 2 k – 9 = 1

⇒ 2 k = 10

⇒ k = 5

and – (8 – k)k + 10 = a

⇒ a = – (8 – 5)5 + 10 = – 3 × 5 + 10 = – 15 + 10 = – 5

Hence, k = 5 and a = – 5.

Brain liest plz