Question

class9force
plz solve it

Answer 1

mass of particle m=0.3kg
applied force =f=kx
k=15N/m
x=20cm=0.2m
now
let acc be=a
using Newton second law of motion, we get
f=ma=kx=ma
15×0·2=0·3×a
3=0·3a
a=10m/s^2