Question

classify the following numbers as rational or irrational root 27 full sum I want

Answer 1

Concept:

The number which can be presented as p/q where p,q are integers and q is not equal to 0, is called Rational Number and if we cannot present a number in this way then that number is called an Irrational number.

Square root of any number which is not a perfect square number is a irrational number.

Product of an irrational number and a rational number gives an irrational number.

Given:

The given number is $\sqrt{27}$.

Find:

We have to classify that the above given number is a rational number or an irrational number.

Solution:

Given the number is $\sqrt{27}$

We know that, 27 = 9*3

Square rooting the number we get,

$\sqrt{27}=\sqrt{9\times3}=3\sqrt3$

Here 3 is a rational number and $\sqrt3$ is an irrational number. Since their product gives an irrational number.

So, $3\sqrt3$ is an irrational number.

Hence, $\mathbf{\sqrt{27}}$ is an irrational number.

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Answer 2

Answer: $\sqrt{27}$ is an irrational number

Step-by-step explanation:

A rational number is one that can be expressed as p/q, where p, q are integers, and q is not equal to 0. If a number cannot be expressed in this way, it is referred to as an irrational number. Any number that has a square root that is not a perfect square number is irrational. An irrational number is produced when a rational number is added to an irrational number.

Given, the number is $\sqrt{27}$

Now, to classify whether the given number is a rational number or an irrational number, we will simplify it

$27=3\times 3\times 3\\\Rightarrow \sqrt{27}=\sqrt{3\times 3\times 3}\\\therefore \sqrt{27}=3\sqrt{\times 3}$

Here 3 is a rational number and  $\sqrt{3}$ is an irrational number. Since their product gives an irrational number.

So, $\sqrt{27}$ is an irrational number.

To know more about rational and irrational nos., click on the links below:

https://brainly.in/question/1563578

https://brainly.in/question/8560889

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