Question

clear me with this sum plz

Answer 1

To Find

➩The value of x

Solution:

$\frac{\small \: 2x -\large\:\frac{3}{4} } { \:\small \: 9x + \large\frac{4}{7}} = \large\frac{1}{4}$

$4(\sf 2x -\sf \frac{3}{4}) = 1(\sf 9x -\sf \frac{4}{7})$

$8x - 3 = \sf 9x + \sf \frac{4}{7}$

$8x - 9x = \sf \frac{4}{7} +\sf \frac{3}{1}$

$\bold -1x = \sf \frac{4 + 21}{7}$

$\bold 1x =\sf \frac{ - 25}{ \: 7}$

$\sf \bold x= \bold -3.57 (Approx)$

Answer 2

$\huge \orange \star \red {\textsf{\textbf{ \underline{Solution :- }}}}$

$\: \: \: \: \: \sf :\implies \dfrac{2x - \dfrac{3}{4} }{9x + \dfrac{4}{7} } = \dfrac{1}{4}$

$\: \: \: \: \: \sf :\implies4(2x - \frac{3}{4} ) = 1(9x - \dfrac{4}{7})$

$\: \: \: \: \: \sf :\implies8x - 3 = 9x + \dfrac{4}{7}$

$\: \: \: \: \: \sf :\implies8x - 9x = \dfrac{4}{7} + \dfrac{3}{7}$

$\: \: \: \: \: \sf :\implies- 1x = \dfrac{4 + 21}{7}$

$\: \: \: \: \: \sf :\implies1x = \dfrac{ - 25}{7}$

$\: \: \: \: \: \: \: \: \: \: \: {\blue{\boxed {\pink{ \sf {(x = - 3.71)}}}}}$