Math, asked by abhishekrajput76, 1 year ago

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Answered by Mankuthemonkey01
8
First, we need to find the area of the triangle.

Formula for area of Triangle is :-

 \frac{1}{2}  \times base \times height

Given,

Base = 88cm
Height = 35cm


So, Area = 1/2 × 88 × 35

=> area = 44 × 35

=> area = 1540cm²

area of triangle is 1540cm²

Now, given that area of circle is 40 times of that of the triangle.

So area of circle = 40 × area of triangle

=> area of circle = 40 × 1540

=> area of circle = 61600cm²


But the area of circle is πr²

=> πr² = 61600

=> r² = 61600/ π

Putting π as 22/7,

r² = 61600 ÷ 22/7

=> r² = 61600 × 7/22

=> r² = 19600

=> r = √19600

=> r = 140cm

Radius = 140cm

Now we have to find the circumference,

we know that circumference = 2πr

=> circumference = 2 × 22/7 × 140

=> circumference = 880 cm


Your answer :-

Radius = 140 cm

Circumference = 880cm


Hope it helps dear friend ☺️✌️
Answered by Shubhendu8898
9

Given ,

Height of  Δ = 35 cm

Base  of  Δ = 88 cm

We know that,

Area  of  Δ = 1/2 × height × base

                  = 1/2  × 88 × 35

                   = 1540 cm²

Area  of  Circle = πr² ,

Where  r  is  radius  of  circle,

According to question

Area  of circle  =  40 × area  of  Δ

     πr² = 40 × 1540

     πr² = 61600

       r² = 61600/π

      r² = 61600 × 7/22

      r² = 19600

      r = 140 cm

Now,

Circumference  of  Circle = 2πr

                                          = 2 × 22/7 × 140

                                          = 880 cm

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