Environmental Sciences, asked by manojbhise3302, 10 months ago

Cloud effective radius inversely related to droplet

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Answered by alien19
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The cloud drop effective radius (alternatively cloud effective radius or effective radius) is a weighted mean of the size distribution of cloud droplets.The term was defined in 1974 by James E. Hansen and Larry Travis as the ratio of the third to the second moment of a droplet size distribution to aid in the inversion of remotely sensed data. Physically, it is an area weighted radius of the cloud drop particles.

Mathematically, this can be expressed as {\displaystyle r_{e}={\dfrac {\int \limits _{0}^{\infty }\pi \cdot r^{3}\cdot n(r)\,dr}{\int \limits _{0}^{\infty }\pi \cdot r^{2}\cdot n(r)\,dr}}} {\displaystyle r_{e}={\dfrac {\int \limits _{0}^{\infty }\pi \cdot r^{3}\cdot n(r)\,dr}{\int \limits _{0}^{\infty }\pi \cdot r^{2}\cdot n(r)\,dr}}}.

The global effective particle radius has different values for water and ice clouds: the former is around 14 μm, whereas for ice it is around 25 μm. Studies also indicate that the effective cloud droplet radius is larger over oceans than over ground by 15%-20%. By contrast, the difference in the ice particle size over land and oceans is much smaller (only 5%).

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