Question

cmon man anyone..help me q.no.28. give ans in pic

Answer 1

Heya!!

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= x^3 + y^3 + 64 - 12xy

= x^3 + y^3 + 4^3 - 3*x*y*4

By identity ;

= (a^3 + b^3 + c^3 - 3abc)

= (a+b+c) (a^2 + b^2 + c^2 - ab - bc - ac)

= (x+ y + 4) (x^2 + y^2 + 16 - 4x - 4y - xy)

= (-4+4) (x^2 + y^2 + 16 - 4x - 4y - xy)

= 0 * (x^2 + y^2 + 16 - 4x - 4y - xy)

= 0

Hope it helps uh :)

Answer 2

$\huge{hey}$


$\huge{here \: is \: the \: answer}$
⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇

$\bf{see \: in \: attachment}$

$\huge \bf{hope \: it \: helps}$

$\huge \boxed{thanks}$