AB and CD are two chords of a circle of radius r such that Ab is equal to 2 AC if p and q are the distances of a b and AC from the centre prove that four Q square is equal to p square + 3 square
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Posted By

Ishita Jaiswal
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Subject: Math (Circles)
Status: Closed | Replies: 1
2nd Mar 2015, 1:41 PM
AB and AC are two chords of a circle of radius r such that AB = 2AC. If p and q are the distances of AB and AC repectively from the centre, prove that 4q2 = p2 + 3r2.
Smartlearning Expert3rd Mar 2015, 6:06 PM
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Posted By

Ishita Jaiswal
Rate this Question
Currently 5.00/5
Rating: 5.0/5 (4 votes cast)
Subject: Math (Circles)
Status: Closed | Replies: 1
2nd Mar 2015, 1:41 PM
AB and AC are two chords of a circle of radius r such that AB = 2AC. If p and q are the distances of AB and AC repectively from the centre, prove that 4q2 = p2 + 3r2.
Smartlearning Expert3rd Mar 2015, 6:06 PM
Accepted Answer:

Copyright © www.Smartlearning.in
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