(Co(NH3)5Cl)Cl oxidation number of co
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Explanation:
Answer: Oxidation state can be found by finding the charge on the transitional metal in the complex ion, Therefore in [Co(NH3)5Cl]2+ solving [ Co + (5*0) + (-1) = +2 ] gives Co=+3. Therefore the oxidation state of Co is +3.
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Given:
The given complex is .
To find:
The oxidation state of Co.
Solution:
The complex is .
Let the oxidation state of Co is x.
The ammonium ligands have 0 charges.
The charge of the chloride ligands is -1.
The overall charge of the complex is 0.
Hence we can write-
The value of x is +2.
Hence the oxidation number of Co is +2.
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