Math, asked by sanobarshaikh2827, 1 year ago


Co-ordinate of point P on a number line is - 7. Find the co-ordinates of points on thenumber line which are at a distance of 8 units from point P.

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Answers

Answered by Anonymous
8

Hi beautiful

Here is ur answer

If you move along the number line

right at a distance of 8 units from P,

the coordinates of the point will be 1.

If you move along the number line

Left at a distance of 8 units from P,

the coordinates of the point will be

-15.

I hope this answer helps you

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Answer:

1 & - 15

Step-by-step explanation:

Co-ordinate of point P on a number line is - 7. Find the co-ordinates of points on the number line which are at a distance of 8 units from point P.

Number line is x - axis

Point P on number line - 7 is

actually ( - 7 , 0)

To find coordinates which are at a distance of 8 units on number line itself

only x co-ordinate will change & y will remain same

let say new point would be ( x , 0)

Distance between (x , 0 ) & (-7 , 0 ) = 8

Distance = √ (x -(-7))² + (0-0)²

=> 8 = √((x + 7)²

Squaring both sides

=> (x + 7)² = 64

Taking square root both sides

x + 7 = ±8

=> x + 7 = 8 or x + 7 = -8

=> x = 1 or x = -15

Co-ordinates of point of number line which are at a distance of 8 units from point P are 1 & - 15


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Answered by rahman786khalilu
7

Step-by-step explanation:

disrance can never be negative so there are two points which are 8 units from -7

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