Physics, asked by saumendips5702, 11 months ago

Coefficient of apparent expansions of mercury is 0.18 xx 10^(-3)//^(0)C. If the density of mercury at 0^(0)C is 13.6 g//c c its density at 473K will be

Answers

Answered by newmerryn
0

Answer:

Co-efficient of volume expansion of

Density of mg at

To find :

Density at

We Know

ρ=

(1+r

0

t)

ρ

0

Where

ρ → Density at any temp other than 0

C

ρ → Density at 0

C

r

0

→ co-efficient of volume expansion.

t→

temp at which density is to be calculated.

ρ=

1+0.18×200

13.6

=

1.036

13.6

=13.11g/cc

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